If the running speed of a machine is 600 CPM, and there is a peak at "8X", what is the frequency of that peak?

Prepare for the Mobius Vibration Analysis Category-I Certification. Use flashcards and multiple choice questions, each question with hints and explanations, to excel in your exam!

To determine the correct frequency of the peak at "8X," it is essential to understand the relationship between the running speed of the machine and the harmonic frequency. The running speed is given as 600 CPM (cycles per minute). The notation "8X" indicates the peak is occurring at the 8th harmonic of the fundamental frequency of the machine.

First, calculate the fundamental frequency in CPM, which in this case is the same as the running speed: 600 CPM. To find the frequency at "8X," you multiply the running speed by 8:

8X frequency = 8 * 600 CPM = 4800 CPM.

Next, to convert CPM to Hz (cycles per second), you divide by 60 (since there are 60 seconds in a minute):

4800 CPM = 4800 / 60 = 80 Hz.

Thus, the frequency at which the peak occurs is 4800 CPM, which is equivalent to 80 Hz. This matches the first choice, making it the correct answer.

The other options provide incorrect values that do not align with the calculations made. They may differ in either the CPM or Hz representation or both, which indicates a misunderstanding of how to calculate harmonic frequencies from the running

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